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Instant Download Oracle : 1Z0-007 Questions & Answers as PDF & Test Engine
- Exam Code: 1Z0-007
- Exam Name: Introduction to Oracle9i: SQL
- Updated: Sep 01, 2026
- No. of Questions: 110 Questions and Answers
- Download Limit: Unlimited
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Oracle 1Z0-007 Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Creating Views | - Create, alter, drop views - DML through views |
| Creating Other Database Objects | - Sequences - Indexes - Synonyms |
| Single–Row Functions | - Use character, number, and date functions in SELECT statements - Use conversion functions |
| Writing Basic SQL SELECT Statements | - Capabilities of SQL SELECT statements - Differentiate between SQL and iSQL*Plus commands - Execute a basic SELECT statement |
| Displaying Data from Multiple Tables | - Equality and nonequality joins - Outer joins - Self–join |
| Subqueries | - Single–row and multiple–row subqueries - Define subqueries |
| Restricting and Sorting Data | - Sort rows retrieved by a query - Limit rows retrieved by a query |
| Producing Readable Output with iSQL*Plus | - Substitution variables - Script files |
| Manipulating Data | - INSERT rows - UPDATE rows - MERGE rows - DELETE rows |
Oracle Introduction to Oracle9i: SQL Sample Questions:
Question 1
You need to design a student registration database that contains several tables storing academic information.
The STUDENTS table stores information about a student. The STUDENT_GRADES table stores information about the student's grades. Both of the tables have a column named STUDENT_ID. The STUDENT_ID column in the STUDENTS table is a primary key.
You need to create a foreign key on the STUDENT_ID column of the STUDENT_GRADES table that points to the STUDENT_ID column of the STUDENTS table. Which statement creates the foreign key?
A. CREATE TABLE student_grades(student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3), student_id_fk FOREIGN KEY (student_id) REFERENCES students(student_id));
B. CREATE TABLE student_grades(student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3), CONSTRAINT FOREIGN KEY (student_id) REFERENCES students(student_id));
C. CREATE TABLE student_grades(student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3), CONSTRAINT student_id_fk FOREIGN KEY (student_id) REFERENCES students(student_id));
D. CREATE TABLE student_grades (student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3), CONSTRAINT student_id_fk REFERENCES (student_id) FOREIGN KEY students(student_id));
Question 2
Evaluate the SQL statement:
SELECT ROUND(45.953, -1), TRUNC(45.936, 2)
FROM dual;
Which values are displayed?
A. 50 and 45.93
B. 50 and 45.9
C. 45 and 45.93
D. 46 and 45
E. 45.95 and 45.93
F. 46 and 45.93
Question 3
The ORDERS table has these columns:
The ORDERS table tracks the Order number, the order total, and the customer to whom the Order belongs. Which two statements retrieve orders with an inclusive total that ranges between 100.00 and 2000.00 dollars? (Choose two.)
A. SELECT customer_id, order_id, order_total FROM orders WHERE order_total >= 100 and order_total <= 2000;
B. SELECT customer_id, order_id, order_total FROM orders WHERE order_total >= 100 and <= 2000;
C. SELECT customer_id, order_id, order_total FROM orders HAVING order_total BETWEEN 100 and 2000;
D. SELECT customer_id, order_id, order_total FROM orders WHERE order_total BETWEEN 100 and 2000;
E. SELECT customer_id, order_id, order_total FROM orders RANGE ON order_total (100 AND 2000) INCLUSIVE;
Question 4
Which clause should you use to exclude group results?
A. RESTRICT
B. GROUP BY
C. ORDER BY
D. HAVING
E. WHERE
Question 5
Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables:
Which UPDATE statement is valid?
A. UPDATE new_employees SET name = (SELECT last_name||
first_name
FROM employees
WHERE employee_id
=180)
WHERE employee_id =(SELECT employee_id
FROM new employees);
B. UPDATE new_employees SET name = (SELECT
last_name||first_name
FROM employees)
WHERE employee_id =180;
C. UPDATE new_employees SET name = (Select last_name||
first_name
FROM employees
Where employee_id
=180)
WHERE employee_id =180;
D. UPDATE new_employees SET name = (SELECT last name||
first_name
FROM employees
WHERE employee_id=
(SELECT employee_id
FROM new_employees))
WHERE employee_id
=180;
Solutions:
| Question 1 Answer: C | Question 2 Answer: A | Question 3 Answer: A,D | Question 4 Answer: D | Question 5 Answer: C |
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